ߏߔߌ߲ߛߑߕߙߌߕߑߡߊߔ ߛߌ߲ߞߐ߲ OpenStreetMap

dclarks ߕߋ߬ߟߋ߲

ߕߋ߬ߟߋ߲ ߟߊ߬ߘߏ߲߬ߠߌ߲߬ߣߐ ߞߐߟߕߊ ߟߎ߬

Rota de ônibus

ߊ߬ ߟߊߦߟߍ߬ߣߍ߲߬ ߦߋ߫ dclarks ߓߟߏ߫ 12 April 2016 ߦߋ߫ Brazilian Portuguese (Português do Brasil) ߟߋ߬ ߘߐ߫ ߟߊ߬ߞߎ߬ߘߦߊ߬ߟߌ߬ ߞߐߟߕߊ 24 September 2016 ߘߐ߫

Inter 2 (023) - Sentido anti-horário: [osm.org/relation/6130551#map=13/-25.4551/-49.2406: ] (osm.org/relation/6130551#map=13/-25.4551/-49.2406)

Inter 2 (022) - Sentido Horário: http://www.openstreetmap.org/relation/3512649#map=13/-25.4551/-49.2587&layers=N

Centro politécnico (469) http://www.openstreetmap.org/relation/5982647#map=15/-25.4394/-49.2430

Santa Bárbara (461) http://www.openstreetmap.org/relation/3541051#map=16/-25.4547/-49.2264

Estudantes (466) http://www.openstreetmap.org/relation/3512653#map=14/-25.4368/-49.2426

Universidades (165) http://www.openstreetmap.org/relation/3512651#map=16/-25.4516/-49.2423

Petrópolis (462) Existe rota distinta no final dela quando o ônibus for Petrópolis/Ouro Verde, vai até o final da Rua Zacarias Gomes de Souza http://www.openstreetmap.org/relation/3512654#map=17/-25.45294/-49.22625

Circular Centro Sentido Horário (001) http://www.openstreetmap.org/relation/5973797

Circular Centro Sentido Anti Horário (002) http://www.openstreetmap.org/relation/5973827

Cabral/Osório (207) http://www.openstreetmap.org/relation/3344563#map=17/-25.40712/-49.25004

Interbairros II (Horário) http://www.openstreetmap.org/relation/3512647#map=13/-25.4401/-49.2591

Interbairros V (050) http://www.openstreetmap.org/relation/3512652#map=14/-25.4630/-49.2709&layers=N

Caiua/Faz/Centro (706) http://www.openstreetmap.org/relation/5974098#map=13/-25.4630/-49.2651&layers=N

Centenário/C. Comprido (303) http://www.openstreetmap.org/relation/14680#map=13/-25.4419/-49.2692&layers=N

Trindade (321) [osm.org/relation/6607298#map=16/-25.4515/-49.2067&layers=N] (osm.org/relation/6607298#map=16/-25.4515/-49.2067&layers=N)

C. Imbuia / Pq. Barigui (393) [osm.org/relation/6607797#map=14/-25.4424/-49.2560&layers=N] (osm.org/relation/6607797#map=14/-25.4424/-49.2560&layers=N)